What is the tangent of f(x)=(x^2)/(x+8),(1, 1/9) ?

The tangent of f(x)=(x^2)/(x+8),(1, 1/9) is y= 17/81 x-8/81

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tangent of f(x)=(x^2)/(x+8),(1, 1/9)

tangent of

f (x) = \frac{x ^{2}}{x + 8}, (1, \frac{1}{9})

y = \frac{17}{81} x - \frac{8}{81}

Solution steps

Find the slope of

f (x) = \frac{x ^{2}}{x + 8} : \frac{df ( x )}{d x} = \frac{x ^{2} + 16 x}{( x + 8 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{17}{81}

Find the line with slope m=

\frac{17}{81}

and passing through

(1, \frac{1}{9}) : y = \frac{17}{81} x - \frac{8}{81}

y = \frac{17}{81} x - \frac{8}{81}

y^{^{'}} = y^{2} + 1

f (x) = x 4 - x

\frac{d}{d x} (2 x + 3 y)

x \to 2 π lim (\frac{sin ( x )}{x})

\frac{\partial}{\partial y} (x ln (x y))

What is the tangent of f(x)=(x^2)/(x+8),(1, 1/9) ?
The tangent of f(x)=(x^2)/(x+8),(1, 1/9) is y= 17/81 x-8/81