What is (d^2)/(dx^2)((4x^2+9x)cos(x)) ?

The answer to (d^2)/(dx^2)((4x^2+9x)cos(x)) is -4x^2cos(x)-16xsin(x)-9xcos(x)-18sin(x)+8cos(x)

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(d^2)/(dx^2)((4x^2+9x)cos(x))

\frac{d ^{2}}{d x ^{2}} ((4 x^{2} + 9 x) cos (x))

- 4 x^{2} cos (x) - 16 x sin (x) - 9 x cos (x) - 18 sin (x) + 8 cos (x)

Solution steps

\frac{d ^{2}}{d x ^{2}} ((4 x^{2} + 9 x) cos (x))

\frac{d}{d x} ((4 x^{2} + 9 x) cos (x)) = cos (x) (8 x + 9) - sin (x) (4 x^{2} + 9 x)

= \frac{d}{d x} (cos (x) (8 x + 9) - sin (x) (4 x^{2} + 9 x))

\frac{d}{d x} (cos (x) (8 x + 9) - sin (x) (4 x^{2} + 9 x)) = - 4 x^{2} cos (x) - 16 x sin (x) - 9 x cos (x) - 18 sin (x) + 8 cos (x)

= - 4 x^{2} cos (x) - 16 x sin (x) - 9 x cos (x) - 18 sin (x) + 8 cos (x)

e^{x} y \cdot \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

\int \frac{1}{( 1 + x ) ^{\frac{3}{2}}} d x

\frac{d ^{3} y}{d x ^{3}} = 4 x^{3} + x

\frac{d ^{2}}{d x ^{2}} (\frac{6}{7 x ^{4}})

\int 2 π x^{3} 1 + 9 x^{4} d x

What is (d^2)/(dx^2)((4x^2+9x)cos(x)) ?
The answer to (d^2)/(dx^2)((4x^2+9x)cos(x)) is -4x^2cos(x)-16xsin(x)-9xcos(x)-18sin(x)+8cos(x)