What is the derivative of e^{x^2-9} ?

The derivative of e^{x^2-9} is e^{x^2-9}*2x

What is the first derivative of e^{x^2-9} ?

The first derivative of e^{x^2-9} is e^{x^2-9}*2x

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derivative of

e^{x^{2} - 9}

e^{x^{2} - 9} \cdot 2 x

Solution steps

\frac{d}{d x} (e^{x^{2} - 9})

Apply the chain rule:

e^{x^{2} - 9} \frac{d}{d x} (x^{2} - 9)

= e^{x^{2} - 9} \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= e^{x^{2} - 9} \cdot 2 x

2 x^{4} - x^{3} + 6 x^{2}

a (t) = t^{3} - 12 t

\int_{0}^{\infty} x^{3} e^{- 3 x} d x

\int + x^{2} a^{2} - x^{2} d x

\int \frac{e ^{9 t}}{t} d t

What is the derivative of e^{x^2-9} ?
The derivative of e^{x^2-9} is e^{x^2-9}*2x
What is the first derivative of e^{x^2-9} ?
The first derivative of e^{x^2-9} is e^{x^2-9}*2x