What is (\partial)/(\partial x)((5x-x^2)cos(t)) ?

The answer to (\partial)/(\partial x)((5x-x^2)cos(t)) is cos(t)(5-2x)

Popular >

(\partial)/(\partial x)((5x-x^2)cos(t))

\frac{\partial}{\partial x} ((5 x - x^{2}) cos (t))

cos (t) (5 - 2 x)

Solution steps

\frac{\partial}{\partial x} ((5 x - x^{2}) cos (t))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (t) \frac{\partial}{\partial x} (5 x - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= cos (t) (\frac{\partial}{\partial x} (5 x) - \frac{\partial}{\partial x} (x^{2}))

\frac{\partial}{\partial x} (5 x) = 5

\frac{\partial}{\partial x} (x^{2}) = 2 x

= cos (t) (5 - 2 x)

Y (s) = \frac{s - 2}{s ^{2} - 2 s - 3}

f (x) = - 3 x^{2} + x + 2, at x = 1

\frac{\partial}{\partial x} (\frac{p}{1 + e ^{c o s (x)}})

\int \frac{3 x + 4}{2 x + x ^{2}} d x

\int 3 x - 1 d x

What is (\partial)/(\partial x)((5x-x^2)cos(t)) ?
The answer to (\partial)/(\partial x)((5x-x^2)cos(t)) is cos(t)(5-2x)