What is the d/(dy)(sqrt(y^2-9)) ?

The d/(dy)(sqrt(y^2-9)) is y/(sqrt(y^2-9))

What is the first d/(dy)(sqrt(y^2-9)) ?

The first d/(dy)(sqrt(y^2-9)) is y/(sqrt(y^2-9))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d y} (y^{2} - 9)

\frac{y}{y ^{2} - 9}

Solution steps

\frac{d}{d y} (y^{2} - 9)

Apply the chain rule:

\frac{1}{2 y ^{2} - 9} \frac{d}{d y} (y^{2} - 9)

= \frac{1}{2 y ^{2} - 9} \frac{d}{d y} (y^{2} - 9)

\frac{d}{d y} (y^{2} - 9) = 2 y

= \frac{1}{2 y ^{2} - 9} \cdot 2 y

Simplify

\frac{1}{2 y ^{2} - 9} \cdot 2 y : \frac{y}{y ^{2} - 9}

= \frac{y}{y ^{2} - 9}

\frac{d}{d x} (2^{4 - x^{2}})

\int ln (x) + 2 d x

7 y^{^{'}} - 21 x^{2} = 0

\int_{- 2}^{6} (2 - ∣ x ∣) d x

y^{^{''}} - y = - 1

What is the d/(dy)(sqrt(y^2-9)) ?
The d/(dy)(sqrt(y^2-9)) is y/(sqrt(y^2-9))
What is the first d/(dy)(sqrt(y^2-9)) ?
The first d/(dy)(sqrt(y^2-9)) is y/(sqrt(y^2-9))