What is (\partial)/(\partial x)(2(ln(x))+y) ?

The answer to (\partial)/(\partial x)(2(ln(x))+y) is 2/x

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(\partial)/(\partial x)(2(ln(x))+y)

\frac{\partial}{\partial x} (2 (ln (x)) + y)

\frac{2}{x}

Solution steps

\frac{\partial}{\partial x} (2 (ln (x)) + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 ln (x)) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 ln (x)) = \frac{2}{x}

\frac{\partial}{\partial x} (y) = 0

= \frac{2}{x} + 0

Simplify

= \frac{2}{x}

\frac{\partial}{\partial x} (x (x - 2))

\int \frac{1}{x ( x + 1 )} d x

2 x e^{x^{2}}

\int x^{3} e^{x y}

\int_{6}^{8} \frac{44}{( x - 6 ) ^{3}} d x

What is (\partial)/(\partial x)(2(ln(x))+y) ?
The answer to (\partial)/(\partial x)(2(ln(x))+y) is 2/x