What is the limit as x approaches 0 of 2x^2ln(x) ?

The limit as x approaches 0 of 2x^2ln(x) is Does not exist

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limit as x approaches 0 of 2x^2ln(x)

x \to 0 lim (2 x^{2} ln (x))

Does not exist

Solution steps

x \to 0 lim (2 x^{2} ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2 x^{2} ln (x)) = 0

x \to 0 - lim (2 x^{2} ln (x)) =

Does not exist

= Does not exist

\frac{d}{d x} (5 \frac{5 x}{4 x - 3})

x \to 0 lim ([x] \cdot sin (\frac{1}{x}))

\int \frac{7 x ^{2} + 8 x - 2}{x ^{2} + 2 x} d x

z \to (2 i) lim (z^{2} - z)

f (x) = 2^{x} lo g_{2} (x)

What is the limit as x approaches 0 of 2x^2ln(x) ?
The limit as x approaches 0 of 2x^2ln(x) is Does not exist