Solution
Solution
+1
Solution steps
Take the constant out:
Apply u-substitution
Integral of a constant:
Compute the boundaries:
Simplify
Popular Examples
t^2y^'+y^2=ty,y(1)=-1/2(\partial)/(\partial x)(ln(x-y^2))(dy)/(dx)=(4sec(y))/((x-6)^2)(\partial)/(\partial x)(x^2+xe^{2y}-y)(dx)/(dy)=4(x^2+1)
Frequently Asked Questions (FAQ)
What is the integral from 5 to 8 of 6/(sqrt(x-5)) ?
The integral from 5 to 8 of 6/(sqrt(x-5)) is 12sqrt(3)