What is the derivative of 5/(1-8x) ?

The derivative of 5/(1-8x) is (40)/((1-8x)^2)

What is the first derivative of 5/(1-8x) ?

The first derivative of 5/(1-8x) is (40)/((1-8x)^2)

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derivative of

\frac{5}{1 - 8 x}

\frac{40}{( 1 - 8 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{1 - 8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{1 - 8 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((1 - 8 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 8 x ) ^{2}} \frac{d}{d x} (1 - 8 x)

= - \frac{1}{( 1 - 8 x ) ^{2}} \frac{d}{d x} (1 - 8 x)

\frac{d}{d x} (1 - 8 x) = - 8

= 5 (- \frac{1}{( 1 - 8 x ) ^{2}} (- 8))

Simplify

5 (- \frac{1}{( 1 - 8 x ) ^{2}} (- 8)) : \frac{40}{( 1 - 8 x ) ^{2}}

= \frac{40}{( 1 - 8 x ) ^{2}}

\frac{\partial}{\partial x} (y^{2} e^{x y - 3})

f (x) = ln (arctan (x))

\int (sin (4 x) + cosh (3 x)) d x

\int_{- 1}^{3} (2 x^{2} - x + 5) d x

y = 3 x + 1, (8, 5)

What is the derivative of 5/(1-8x) ?
The derivative of 5/(1-8x) is (40)/((1-8x)^2)
What is the first derivative of 5/(1-8x) ?
The first derivative of 5/(1-8x) is (40)/((1-8x)^2)