What is the derivative of f(x)=2+x ?

The derivative of f(x)=2+x is 1

What is the first derivative of f(x)=2+x ?

The first derivative of f(x)=2+x is 1

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derivative of

f (x) = 2 + x

1

Solution steps

\frac{d}{d x} (2 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d x}{d x}

\frac{d}{d x} (2) = 0

\frac{d x}{d x} = 1

= 0 + 1

Simplify

= 1

(2 x^{3} + y^{3}) d x - 3 x y^{2} d y = 0

\frac{d}{d θ} (sin (θ) cos (θ))

\int e^{s i n (π) x} cos (π) x d x

x \to 1 lim (x^{2} - 2 x - 1)

\int \frac{cos ( x )}{4 + sin ^{2} ( x )} d x

What is the derivative of f(x)=2+x ?
The derivative of f(x)=2+x is 1
What is the first derivative of f(x)=2+x ?
The first derivative of f(x)=2+x is 1