What is the derivative of f(x)=e^{x+1}+7 ?

The derivative of f(x)=e^{x+1}+7 is e^{x+1}

What is the first derivative of f(x)=e^{x+1}+7 ?

The first derivative of f(x)=e^{x+1}+7 is e^{x+1}

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derivative of

f (x) = e^{x + 1} + 7

e^{x + 1}

Solution steps

\frac{d}{d x} (e^{x + 1} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x + 1}) + \frac{d}{d x} (7)

\frac{d}{d x} (e^{x + 1}) = e^{x + 1}

\frac{d}{d x} (7) = 0

= e^{x + 1} + 0

Simplify

= e^{x + 1}

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What is the derivative of f(x)=e^{x+1}+7 ?
The derivative of f(x)=e^{x+1}+7 is e^{x+1}
What is the first derivative of f(x)=e^{x+1}+7 ?
The first derivative of f(x)=e^{x+1}+7 is e^{x+1}