What is the derivative of y=e^{9e^x} ?

The derivative of y=e^{9e^x} is 9e^{9e^x+x}

What is the first derivative of y=e^{9e^x} ?

The first derivative of y=e^{9e^x} is 9e^{9e^x+x}

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derivative of

y = e^{9 e^{x}}

9 e^{9 e^{x} + x}

Solution steps

\frac{d}{d x} (e^{9 e^{x}})

Apply the chain rule:

e^{9 e^{x}} \frac{d}{d x} (9 e^{x})

= e^{9 e^{x}} \frac{d}{d x} (9 e^{x})

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= e^{9 e^{x}} \cdot 9 e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{9 e^{x}} e^{x} = e^{9 e^{x} + x}

= 9 e^{9 e^{x} + x}

x (\frac{d y}{d x}) + y = \frac{1}{y ^{2}}

y = x x

\int \frac{1}{x ^{2}} (ln^{2} (x)) d x

x \to π lim (6)

\frac{d ^{2} Q}{d t ^{2}} - 7 \frac{d Q}{d t} + 5 Q = 0

What is the derivative of y=e^{9e^x} ?
The derivative of y=e^{9e^x} is 9e^{9e^x+x}
What is the first derivative of y=e^{9e^x} ?
The first derivative of y=e^{9e^x} is 9e^{9e^x+x}