What is laplacetransform f(t)=cos(2t) ?

The answer to laplacetransform f(t)=cos(2t) is s/(s^2+4)

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laplacetransform f(t)=cos(2t)

laplace transform

f (t) = cos (2 t)

\frac{s}{s ^{2} + 4}

Solution steps

L {cos (2 t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (2 t)} = \frac{s}{s ^{2} + 2 ^{2}}

= \frac{s}{s ^{2} + 2 ^{2}}

= \frac{s}{s ^{2} + 4}

x y \frac{d y}{d x} = 1

\int + \frac{x}{x ^{2} + 1} d x

\int \frac{1}{y ^{2} - 9} d y

t^{3} sin (2 t)

x \cdot \frac{d y}{d x} - y = x^{2} sin (x)

What is laplacetransform f(t)=cos(2t) ?
The answer to laplacetransform f(t)=cos(2t) is s/(s^2+4)