What is the derivative of ln(16-x^2) ?

The derivative of ln(16-x^2) is -(2x)/(16-x^2)

What is the first derivative of ln(16-x^2) ?

The first derivative of ln(16-x^2) is -(2x)/(16-x^2)

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\frac{d}{d x} (ln (16 - x^{2}))

- \frac{2 x}{16 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (16 - x^{2}))

Apply the chain rule:

\frac{1}{16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

= \frac{1}{16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

\frac{d}{d x} (16 - x^{2}) = - 2 x

= \frac{1}{16 - x ^{2}} (- 2 x)

Simplify

\frac{1}{16 - x ^{2}} (- 2 x) : - \frac{2 x}{16 - x ^{2}}

= - \frac{2 x}{16 - x ^{2}}

\int 2 (2 + x^{2})^{\frac{3}{2}} d x

\int x^{2} (x^{3} + 6)^{6} d x

f (x) = 1 + x^{3}, at x = 2

\frac{d y}{d x} = x - 1

f (x) = \frac{6 x ^{2} + 10}{4 x ^{3}}

What is the derivative of ln(16-x^2) ?
The derivative of ln(16-x^2) is -(2x)/(16-x^2)
What is the first derivative of ln(16-x^2) ?
The first derivative of ln(16-x^2) is -(2x)/(16-x^2)