What is the solution for (dy)/(dx)=xe^{x+y} ?

The solution for (dy)/(dx)=xe^{x+y} is y=-ln(-e^xx+e^x-c_{1})

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(dy)/(dx)=xe^{x+y}

\frac{d y}{d x} = x e^{x + y}

y = - ln (- e^{x} x + e^{x} - c_{1})

Solution steps

\frac{d y}{d x} = x e^{x + y}

Solve separable ODE:

y = - ln (- e^{x} x + e^{x} - c_{1})

y = - ln (- e^{x} x + e^{x} - c_{1})

\frac{7 x ^{2} + 1}{x ^{2} + 5}

\frac{d}{d x} (7 cot (x))

x \to \infty lim (\frac{4}{x ^{2}})

\frac{d y}{d x} = e^{y}

\frac{d}{d x} (e^{2 x} - e^{x})

What is the solution for (dy)/(dx)=xe^{x+y} ?
The solution for (dy)/(dx)=xe^{x+y} is y=-ln(-e^xx+e^x-c_{1})