What is (\partial)/(\partial x)(-y-(2x)/(y^3)) ?

The answer to (\partial)/(\partial x)(-y-(2x)/(y^3)) is -2/(y^3)

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(\partial)/(\partial x)(-y-(2x)/(y^3))

\frac{\partial}{\partial x} (- y - \frac{2 x}{y ^{3}})

- \frac{2}{y ^{3}}

Solution steps

\frac{\partial}{\partial x} (- y - \frac{2 x}{y ^{3}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (\frac{2 x}{y ^{3}})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (\frac{2 x}{y ^{3}}) = \frac{2}{y ^{3}}

= - 0 - \frac{2}{y ^{3}}

Simplify

= - \frac{2}{y ^{3}}

\int \frac{ln ( x + 1 )}{( x + 1 )} d x

\frac{\partial}{\partial x} (x ln (x + 2 y))

\frac{1}{s ^{2} + 6 s + 34}

1 - e^{- t}

cos (x), sin (x), [0, \frac{π}{4}]

What is (\partial)/(\partial x)(-y-(2x)/(y^3)) ?
The answer to (\partial)/(\partial x)(-y-(2x)/(y^3)) is -2/(y^3)