en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-y=2t

Solution

y^{^{'}} - y = 2 t

Solution

y = - 2 (t + 1) + c_{1} e^{t}

Solution steps

y^{'} (t) - y = 2 t

Solve linear ODE:

y = - 2 (t + 1) + c_{1} e^{t}

y = - 2 (t + 1) + c_{1} e^{t}

Graph

Popular Examples

x^2y^'+2xy=25cos^2(x)

x^{2} y^{^{'}} + 2 x y = 25 cos^{2} (x)

tangent of (-8x)/(x^2+1)tangent of

\frac{- 8 x}{x ^{2} + 1}

inverse oflaplace 5/(s(s^2+4s+5))inverse laplace

\frac{5}{s ( s ^{2} + 4 s + 5 )}

integral of (6x+7)/((x+2)^2)

\int \frac{6 x + 7}{( x + 2 ) ^{2}} d x

integral of 1/(x(ln(x))^3)

\int \frac{1}{x ( ln ( x ) ) ^{3}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=2t ?
The solution for y^'-y=2t is y=-2(t+1)+c_{1}e^t