What is the tangent of f(x)= 7/(1-x),\at x=-3 ?

The tangent of f(x)= 7/(1-x),\at x=-3 is y= 7/16 x+49/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 7/(1-x),\at x=-3

tangent of

f (x) = \frac{7}{1 - x}, at x = - 3

y = \frac{7}{16} x + \frac{49}{16}

Solution steps

Find the tangent point:

(- 3, \frac{7}{4})

Find the slope of

f (x) = \frac{7}{1 - x} : \frac{df ( x )}{d x} = \frac{7}{( 1 - x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{16}

Find the line with slope m=

\frac{7}{16}

and passing through

(- 3, \frac{7}{4}) : y = \frac{7}{16} x + \frac{49}{16}

y = \frac{7}{16} x + \frac{49}{16}

8 z^{2} e^{z}

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} + 1}{x ^{2} - 4})

\int \frac{7}{x - 2} d x

e^{x^{3}}

\frac{\partial}{\partial x} (e^{x y z^{3}})

What is the tangent of f(x)= 7/(1-x),\at x=-3 ?
The tangent of f(x)= 7/(1-x),\at x=-3 is y= 7/16 x+49/16