What is the tangent of f(x)=e^{8x}cos(pix),\at x=0 ?

The tangent of f(x)=e^{8x}cos(pix),\at x=0 is y=8x+1

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tangent of f(x)=e^{8x}cos(pix),\at x=0

tangent of

f (x) = e^{8 x} cos (π x), at x = 0

y = 8 x + 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

f (x) = e^{8 x} cos (π x) : \frac{df ( x )}{d x} = 8 e^{8 x} cos (π x) - π e^{8 x} sin (π x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(0, 1) : y = 8 x + 1

y = 8 x + 1

\frac{\partial}{\partial z} (r cos (t))

1 - 2 e^{- 2 t}

\int e^{4 x} 1 + e^{2 x} d x

x \to 3 lim (2 x^{2} + 4 x + 1)

y^{^{''}} - 2 y^{^{'}} + 5 y = 25 x^{2} + 12

What is the tangent of f(x)=e^{8x}cos(pix),\at x=0 ?
The tangent of f(x)=e^{8x}cos(pix),\at x=0 is y=8x+1