What is the d/(dt)(sin^3(t)) ?

The d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)

What is the first d/(dt)(sin^3(t)) ?

The first d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)

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\frac{d}{d t} (sin^{3} (t))

3 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 3 (sin (t))^{2} cos (t)

Simplify

= 3 sin^{2} (t) cos (t)

\frac{d}{d x} (3 x^{2} cos (6 x))

s (t) = 4 2 t^{2} - 4 t + 7

\int (2 x - 5 x^{2}) (2 - 10 x) d x

\int \frac{x + 1}{2 x ^{2} - 6 x + 4} d x

\frac{d}{d x} (2 π (\frac{x}{9.8})^{\frac{1}{2}})

What is the d/(dt)(sin^3(t)) ?
The d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)
What is the first d/(dt)(sin^3(t)) ?
The first d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)