What is the derivative of x^y+1 ?

The derivative of x^y+1 is yx^{y-1}

What is the first derivative of x^y+1 ?

The first derivative of x^y+1 is yx^{y-1}

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derivative of

x^{y} + 1

y x^{y - 1}

Solution steps

\frac{d}{d x} (x^{y} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{y}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{y}) = y x^{y - 1}

\frac{d}{d x} (1) = 0

= y x^{y - 1} + 0

Simplify

= y x^{y - 1}

f (x) = e^{2 x} - x^{2} - 1

ln (x^{7})

\int_{0}^{4} x^{3} d x

\int - (x - 3)^{2} d x

\frac{d}{d x} (y^{2} - 2 y cos (x))

What is the derivative of x^y+1 ?
The derivative of x^y+1 is yx^{y-1}
What is the first derivative of x^y+1 ?
The first derivative of x^y+1 is yx^{y-1}