What is area y=10x^4-10x^2,y=9x^2 ?

The answer to area y=10x^4-10x^2,y=9x^2 is (361sqrt(38))/(75sqrt(5))

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area y=10x^4-10x^2,y=9x^2

area

y = 10 x^{4} - 10 x^{2}, y = 9 x^{2}

\frac{361 38}{75 5}

Decimal

13.26944 \dots

Solution steps

Apply the area formula:

\int_{- \frac{19}{10}}^{\frac{19}{10}} 10 x^{4} - 19 x^{2} d x

Solve

\int_{- \frac{19}{10}}^{\frac{19}{10}} 10 x^{4} - 19 x^{2} d x : \frac{361 38}{75 5}

The area is:

= \frac{361 38}{75 5}

\int 1 + (cos (x))^{2} d x

\int_{0}^{2} \frac{3}{4 x ^{2} + 5 x + 1} d x

\frac{\partial}{\partial x} (f (x))

\int \frac{1}{( x - 1 ) ^{3}} d x

\frac{d}{d x} (\frac{x ^{3}}{11})

What is area y=10x^4-10x^2,y=9x^2 ?
The answer to area y=10x^4-10x^2,y=9x^2 is (361sqrt(38))/(75sqrt(5))