What is the tangent of x^2+y^2=29,(-5,2) ?

The tangent of x^2+y^2=29,(-5,2) is y= 5/2 x+29/2

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tangent of x^2+y^2=29,(-5,2)

tangent of

x^{2} + y^{2} = 29, (- 5, 2)

y = \frac{5}{2} x + \frac{29}{2}

Solution steps

Find the slope of

x^{2} + y^{2} = 29 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{2}

Find the line with slope m=

\frac{5}{2}

and passing through

(- 5, 2) : y = \frac{5}{2} x + \frac{29}{2}

y = \frac{5}{2} x + \frac{29}{2}

\int_{0}^{1} \frac{x ^{2}}{1 + x ^{6}} d x

\int e^{- 2 l n (x)} d x

\frac{\partial}{\partial x} (e^{x z} + x y)

(x^{2} + 4) \frac{d y}{d x} = x y

\frac{d y}{d x} = x y + 1

What is the tangent of x^2+y^2=29,(-5,2) ?
The tangent of x^2+y^2=29,(-5,2) is y= 5/2 x+29/2