What is the derivative of (x^3+7e^x) ?

The derivative of (x^3+7e^x) is 3x^2e^x+e^x(x^3+7)

What is the first derivative of (x^3+7e^x) ?

The first derivative of (x^3+7e^x) is 3x^2e^x+e^x(x^3+7)

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\frac{d}{d x} ((x^{3} + 7) e^{x})

3 x^{2} e^{x} + e^{x} (x^{3} + 7)

Solution steps

\frac{d}{d x} ((x^{3} + 7) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} + 7, g = e^{x}

= \frac{d}{d x} (x^{3} + 7) e^{x} + \frac{d}{d x} (e^{x}) (x^{3} + 7)

\frac{d}{d x} (x^{3} + 7) = 3 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 3 x^{2} e^{x} + e^{x} (x^{3} + 7)

t e^{2 t} sin (6 t)

\int 8 x^{2} + 3 x - 5 d x

y^{^{'}} = 4 x + y, y (0) = 5

y = - 3 x^{2}, (- 4, - 48)

\int_{0}^{1} t e^{t} d t

What is the derivative of (x^3+7e^x) ?
The derivative of (x^3+7e^x) is 3x^2e^x+e^x(x^3+7)
What is the first derivative of (x^3+7e^x) ?
The first derivative of (x^3+7e^x) is 3x^2e^x+e^x(x^3+7)