What is the limit as x approaches 4 of (x^3-6)/(x-4) ?

The limit as x approaches 4 of (x^3-6)/(x-4) is diverges

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limit as x approaches 4 of (x^3-6)/(x-4)

x \to 4 lim (\frac{x ^{3} - 6}{x - 4})

diverges

Solution steps

x \to 4 lim (\frac{x ^{3} - 6}{x - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{x ^{3} - 6}{x - 4}) = \infty

x \to 4 - lim (\frac{x ^{3} - 6}{x - 4}) = - \infty

= diverges

x \to - 3 lim (\frac{x}{x - 3})

f (x) = - 6 x^{3}

x \to 1 lim (\frac{6 x ^{2} + 12 x - 18}{2 x - 2})

\int_{- 1}^{2} \frac{2}{( 2 x + 4 ) ^{3}} d x

\frac{\partial}{\partial y} (- sin (x^{2} y) \cdot 2 y x)

What is the limit as x approaches 4 of (x^3-6)/(x-4) ?
The limit as x approaches 4 of (x^3-6)/(x-4) is diverges