What is the derivative of f(θ)=cot^2(sin(θ)) ?

The derivative of f(θ)=cot^2(sin(θ)) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)

What is the first derivative of f(θ)=cot^2(sin(θ)) ?

The first derivative of f(θ)=cot^2(sin(θ)) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)

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derivative of

f (θ) = cot^{2} (sin (θ))

- 2 csc^{2} (sin (θ)) cot (sin (θ)) cos (θ)

Solution steps

\frac{d}{d θ} (cot^{2} (sin (θ)))

Apply the chain rule:

2 cot (sin (θ)) \frac{d}{d θ} (cot (sin (θ)))

= 2 cot (sin (θ)) \frac{d}{d θ} (cot (sin (θ)))

\frac{d}{d θ} (cot (sin (θ))) = - csc^{2} (sin (θ)) cos (θ)

= 2 cot (sin (θ)) (- csc^{2} (sin (θ)) cos (θ))

Simplify

= - 2 csc^{2} (sin (θ)) cot (sin (θ)) cos (θ)

\frac{\partial}{\partial y} (ln (x^{2} + y^{4}))

\frac{\partial}{\partial z} (- 2 x y z^{- 1})

\frac{\partial}{\partial x} (x y + y)

\frac{d}{d x} (x^{3} y^{3})

\frac{\partial}{\partial x} (3 x e^{x y})

What is the derivative of f(θ)=cot^2(sin(θ)) ?
The derivative of f(θ)=cot^2(sin(θ)) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)
What is the first derivative of f(θ)=cot^2(sin(θ)) ?
The first derivative of f(θ)=cot^2(sin(θ)) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)