What is the tangent of y=2sin(x),\at x= pi/4 ?

The tangent of y=2sin(x),\at x= pi/4 is y=sqrt(2)x+sqrt(2)-pi/(2sqrt(2))

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tangent of y=2sin(x),\at x= pi/4

tangent of

y = 2 sin (x), at x = \frac{π}{4}

y = 2 x + 2 - \frac{π}{2 2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 2)

Find the slope of

y = 2 sin (x) : \frac{d y}{d x} = 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 2) : y = 2 x + 2 - \frac{π}{2 2}

y = 2 x + 2 - \frac{π}{2 2}

\int sec^{3} (x) tan^{2} (x) d x

x \to 2 + lim (4)

y = 3 8 x^{2}

x \to 2 + lim (\frac{1}{x ^{3} - 2 x ^{2}})

(x tan (x))^{^{'}}

What is the tangent of y=2sin(x),\at x= pi/4 ?
The tangent of y=2sin(x),\at x= pi/4 is y=sqrt(2)x+sqrt(2)-pi/(2sqrt(2))