What is the integral of \sqrt[3]{t} ?

The integral of \sqrt[3]{t} is 3/4 t^{4/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[3]{t}

\int 3 t d t

\frac{3}{4} t^{\frac{4}{3}} + C

Solution steps

\int 3 t d t

Apply the Power Rule

: \frac{3}{4} t^{\frac{4}{3}}

= \frac{3}{4} t^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} t^{\frac{4}{3}} + C

3 x - 1

\frac{d}{d x} (x^{\frac{1}{3}} + 3)

\int 6 e^{3} d x

\int e^{4 x + e^{4 x}} d x

y^{^{'}} + \frac{1}{20 x} y = - 9.81

What is the integral of \sqrt[3]{t} ?
The integral of \sqrt[3]{t} is 3/4 t^{4/3}+C