What is the solution for (dy)/(dx)=e^{x-y},y(0)=2 ?

The solution for (dy)/(dx)=e^{x-y},y(0)=2 is y=ln(e^x+e^2-1)

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(dy)/(dx)=e^{x-y},y(0)=2

\frac{d y}{d x} = e^{x - y}, y (0) = 2

y = ln (e^{x} + e^{2} - 1)

Solution steps

\frac{d y}{d x} = e^{x - y}

Solve separable ODE:

y = ln (e^{x} + e^{2} - 1)

y = ln (e^{x} + e^{2} - 1)

x \to 11 - lim (x - 11)

e^{x^{x^{2}}}

\frac{\partial}{\partial x} (\frac{e ^{x}}{1 - e ^{x}})

f (x) = sec (x), at x = \frac{π}{3}

\frac{d ^{2} y}{d x ^{2}}, 3 x y + y^{2} = 7

What is the solution for (dy)/(dx)=e^{x-y},y(0)=2 ?
The solution for (dy)/(dx)=e^{x-y},y(0)=2 is y=ln(e^x+e^2-1)