What is the integral from-ln(4) to 0 of 2sqrt(3)e^t ?

The integral from-ln(4) to 0 of 2sqrt(3)e^t is (3sqrt(3))/2

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integral from-ln(4) to 0 of 2sqrt(3)e^t

\int_{- l n (4)}^{0} 23 e^{t} d t

\frac{3 3}{2}

Decimal

2.59807 \dots

Solution steps

\int_{- l n (4)}^{0} 23 e^{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 23 \cdot \int_{- l n (4)}^{0} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= 23 [e^{t}]_{- l n (4)}^{0}

Simplify

ln (4) : 2 ln (2)

= 23 [e^{t}]_{- 2 l n (2)}^{0}

Compute the boundaries:

\frac{3}{4}

= 23 \frac{3}{4}

Simplify

= \frac{3 3}{2}

\frac{\partial}{\partial z} (sin (x yz))

\frac{\partial}{\partial x} (e^{13 x y})

n = 1 \sum \infty \frac{cos ( n \cdot π )}{n ^{\frac{3}{8}}}

x \to 0 lim (\frac{sin ( π )}{x})

\frac{d}{d x} (cos (x^{2} y))

What is the integral from-ln(4) to 0 of 2sqrt(3)e^t ?
The integral from-ln(4) to 0 of 2sqrt(3)e^t is (3sqrt(3))/2