What is the integral of 4tan^2(θ) ?

The integral of 4tan^2(θ) is 4(-θ+tan(θ))+C

Popular >

integral of 4tan^2(θ)

\int 4 tan^{2} (θ) d θ

4 (- θ + tan (θ)) + C

Solution steps

\int 4 tan^{2} (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int tan^{2} (θ) d θ

Rewrite using trig identities

= 4 \cdot \int - 1 + sec^{2} (θ) d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 (- \int 1 d θ + \int sec^{2} (θ) d θ)

\int 1 d θ = θ

\int sec^{2} (θ) d θ = tan (θ)

= 4 (- θ + tan (θ))

Add a constant to the solution

= 4 (- θ + tan (θ)) + C

\frac{\partial}{\partial x} (sin (3 x^{3} y - 5 x y^{3}))

f (x) = 7 e^{x} cos (x), (0, 7)

\int cos^{7} (7 - x) sin (7 - x) d x

\int_{1}^{2} 15 x^{2} 2^{x^{3}} d x

(5 t + e^{t}) (3 - t)