What is the derivative of sin(θ)+csc(θ) ?

The derivative of sin(θ)+csc(θ) is cos(θ)-cot(θ)csc(θ)

What is the first derivative of sin(θ)+csc(θ) ?

The first derivative of sin(θ)+csc(θ) is cos(θ)-cot(θ)csc(θ)

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derivative of

sin (θ) + csc (θ)

cos (θ) - cot (θ) csc (θ)

Solution steps

\frac{d}{d θ} (sin (θ) + csc (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sin (θ)) + \frac{d}{d θ} (csc (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (csc (θ)) = - cot (θ) csc (θ)

= cos (θ) - cot (θ) csc (θ)

\frac{d}{d x} (\frac{a ^{2} + x ^{2}}{a ^{2} - x ^{2}})

\int_{- 1}^{0} 2 - e^{- x} d x

\frac{x}{x ^{2} + 4}

\frac{d}{d x} (\frac{x - 3}{x + 3})

\frac{1}{s ^{2} + 2 s}

What is the derivative of sin(θ)+csc(θ) ?
The derivative of sin(θ)+csc(θ) is cos(θ)-cot(θ)csc(θ)
What is the first derivative of sin(θ)+csc(θ) ?
The first derivative of sin(θ)+csc(θ) is cos(θ)-cot(θ)csc(θ)