What is the derivative of 7x^3-5x+8 ?

The derivative of 7x^3-5x+8 is 21x^2-5

What is the first derivative of 7x^3-5x+8 ?

The first derivative of 7x^3-5x+8 is 21x^2-5

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\frac{d}{d x} (7 x^{3} - 5 x + 8)

21 x^{2} - 5

Solution steps

\frac{d}{d x} (7 x^{3} - 5 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x^{3}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (8)

\frac{d}{d x} (7 x^{3}) = 21 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (8) = 0

= 21 x^{2} - 5 + 0

Simplify

= 21 x^{2} - 5

x \to 2 lim (- 1.999 + 2)

f (x) = - x^{2} + 4 x

\int \frac{10 x - 2}{5 x ^{2} - 2 x} d x

\int \frac{( 1 + sin ( x ) )}{cos ^{2} ( x )} d x

x \to 0 - lim (csc (x))

What is the derivative of 7x^3-5x+8 ?
The derivative of 7x^3-5x+8 is 21x^2-5
What is the first derivative of 7x^3-5x+8 ?
The first derivative of 7x^3-5x+8 is 21x^2-5