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Popular >

y^'=ycos(t)

Solution

y^{^{'}} = y cos (t)

Solution

y = e^{s i n (t) + c_{1}}

Solution steps

y^{'} (t) = y cos (t)

Solve separable ODE:

y = e^{s i n (t) + c_{1}}

y = e^{s i n (t) + c_{1}}

Popular Examples

maclaurin xcos(4x)maclaurin

x cos (4 x)

derivative of (sqrt(s)-5)/(sqrt(s)+1)derivative of

\frac{s - 5}{s + 1}

integral of t^2sin(5t)

\int t^{2} sin (5 t) d t

d/(dn)((1+i)^n+(1-i)^n)

\frac{d}{d n} ((1 + i)^{n} + (1 - i)^{n})

derivative of 4/x-1/(x^3)

\frac{d}{d x} (\frac{4}{x} - \frac{1}{x ^{3}})

Frequently Asked Questions (FAQ)

What is the solution for y^'=ycos(t) ?
The solution for y^'=ycos(t) is y=e^{sin(t)+c_{1}}