What is the derivative of ln(2xdx) ?

The derivative of ln(2xdx) is d(1+ln(2x))

What is the first derivative of ln(2xdx) ?

The first derivative of ln(2xdx) is d(1+ln(2x))

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\frac{d}{d x} (ln (2 x) d x)

d (1 + ln (2 x))

Solution steps

\frac{d}{d x} (ln (2 x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (ln (2 x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = ln (2 x), g = x

= d (\frac{d}{d x} (ln (2 x)) x + \frac{d x}{d x} ln (2 x))

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= d (\frac{1}{x} x + 1 \cdot ln (2 x))

Simplify

d (\frac{1}{x} x + 1 \cdot ln (2 x)) : d (1 + ln (2 x))

= d (1 + ln (2 x))

y = - \frac{5}{9} x + 5, (4, 11)

\frac{\partial}{\partial x} (e^{1 - x y})

\frac{1}{x ^{\frac{1}{3}}}

t - 1

(12 x^{2} - 24 x + 24) e^{x}

What is the derivative of ln(2xdx) ?
The derivative of ln(2xdx) is d(1+ln(2x))
What is the first derivative of ln(2xdx) ?
The first derivative of ln(2xdx) is d(1+ln(2x))