What is the derivative of (3x^5+7/(x^3)) ?

The derivative of (3x^5+7/(x^3)) is (3(2x^5-7))/(x^4)

What is the first derivative of (3x^5+7/(x^3)) ?

The first derivative of (3x^5+7/(x^3)) is (3(2x^5-7))/(x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{3 x ^{5} + 7}{x ^{3}})

\frac{3 ( 2 x ^{5} - 7 )}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{5} + 7}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x ^{5} + 7 ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( 3 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (3 x^{5} + 7) = 15 x^{4}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{15 x ^{4} x ^{3} - 3 x ^{2} ( 3 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

Simplify

\frac{15 x ^{4} x ^{3} - 3 x ^{2} ( 3 x ^{5} + 7 )}{( x ^{3} ) ^{2}} : \frac{3 ( 2 x ^{5} - 7 )}{x ^{4}}

= \frac{3 ( 2 x ^{5} - 7 )}{x ^{4}}

f (x) = e^{x^{6}} - x + 1

\frac{d}{d x} (tan (x^{2}))

\frac{\partial}{\partial y} (x - y^{2})

\frac{d}{d x} ((- cos (4 x) + 1)^{2} + 1)

What is the derivative of (3x^5+7/(x^3)) ?
The derivative of (3x^5+7/(x^3)) is (3(2x^5-7))/(x^4)
What is the first derivative of (3x^5+7/(x^3)) ?
The first derivative of (3x^5+7/(x^3)) is (3(2x^5-7))/(x^4)