What is the tangent of y=x^2-5,(-3,4) ?

The tangent of y=x^2-5,(-3,4) is y=-6x-14

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tangent of y=x^2-5,(-3,4)

tangent of

y = x^{2} - 5, (- 3, 4)

y = - 6 x - 14

Solution steps

Find the slope of

y = x^{2} - 5 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 5

(- 3, 4) : m = - 6

Find the line with slope m=

- 6

and passing through

(- 3, 4) : y = - 6 x - 14

y = - 6 x - 14

(1, 2), (- 2, - 1)

\int \frac{3 x}{1 - x ^{4}} d x

\int 36 e^{6 x} sin (6 x) d x

\int x \cdot 2 x + 1 d x

x \to 0 lim (\frac{3 ( 3 - x ) - 9}{x})

What is the tangent of y=x^2-5,(-3,4) ?
The tangent of y=x^2-5,(-3,4) is y=-6x-14