What is the first derivative of 1-t ?

The first derivative of 1-t is -1

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derivative of 1-t

derivative of

1 - t

- 1

Solution steps

\frac{d}{d t} (1 - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d t}{d t}

\frac{d}{d t} (1) = 0

\frac{d t}{d t} = 1

= 0 - 1

Simplify

= - 1

\int_{0}^{1} \frac{3 t ^{2}}{1 + t ^{3}} d t

x \to 0 lim (e^{- 2 x})

cos (\frac{x}{3})

\int (2 - x)^{2} d x

n = 4 \sum \infty \frac{1}{( n - 4 ) !}