What is the integral from 1 to 3 of x/(sqrt(3+x^2)) ?

The integral from 1 to 3 of x/(sqrt(3+x^2)) is 2(sqrt(3)-1)

Popular >

integral from 1 to 3 of x/(sqrt(3+x^2))

\int_{1}^{3} \frac{x}{3 + x ^{2}} d x

2 (3 - 1)

Decimal Notation

1.46410 \dots

Solution steps

\int_{1}^{3} \frac{x}{3 + x ^{2}} d x

Apply u-substitution

: \int_{4}^{12} \frac{1}{2 u} d u

= \int_{4}^{12} \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{4}^{12} \frac{1}{u} d u

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{4}^{12}

= \frac{1}{2} [2 u^{\frac{1}{2}}]_{4}^{12}

Apply radical rule:

= \frac{1}{2} [2 u]_{4}^{12}

Compute the boundaries:

43 - 4

= \frac{1}{2} (43 - 4)

Simplify

= 2 (3 - 1)

\int_{0}^{x^{3}} (y e^{- \frac{y}{x}}) d y

\int \frac{1}{( x + 4 ) ( x + 2 )} d x

\int \frac{1}{9 - 3 ^{2}} d x

\int \frac{1}{55} x^{4} d x

f (x) = x^{π} \cdot π^{x}

What is the integral from 1 to 3 of x/(sqrt(3+x^2)) ?
The integral from 1 to 3 of x/(sqrt(3+x^2)) is 2(sqrt(3)-1)