(dy)/(dx)=2cos(x)y^3

解答

\frac{d y}{d x} = 2 cos (x) y^{3}

y = - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}, y = - - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}

求解步骤

\frac{d y}{d x} = 2 cos (x) y^{3}

求解可分离方程:

y = - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}, y = - - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}

y = - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}, y = - - \frac{1}{2 ( 2 sin ( x ) + c _{1} )}

\int_{- 2}^{3} \frac{47}{x ^{4}} d x

\frac{\partial}{\partial t} (ln (t^{2} + 1))

d er i v a t i v e \frac{1}{6 x}

\frac{d}{d x} (\frac{3 x}{x ^{2} + 1})

\int x sin (15 - x) d x