What is (\partial)/(\partial x)(-3y(-2x-y-9)) ?

The answer to (\partial)/(\partial x)(-3y(-2x-y-9)) is 6y

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(\partial)/(\partial x)(-3y(-2x-y-9))

\frac{\partial}{\partial x} (- 3 y (- 2 x - y - 9))

6 y

Solution steps

\frac{\partial}{\partial x} (- 3 y (- 2 x - y - 9))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y \frac{\partial}{\partial x} (- 2 x - y - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 3 y (- \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (9))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (9) = 0

= - 3 y (- 2 - 0 - 0)

Simplify

= 6 y

(2 t - 1)^{2}

3 δ (t) + 2 + 4 e^{- 3 t + 2}

\frac{\partial}{\partial x} (\frac{y}{1 + x ^{2}})

(60 + 2 t)^{\frac{2}{3}}

f (x) = 3^{4 x + 5}

What is (\partial)/(\partial x)(-3y(-2x-y-9)) ?
The answer to (\partial)/(\partial x)(-3y(-2x-y-9)) is 6y