What is (\partial)/(\partial z)(sin(z^3)cos(xy)) ?

The answer to (\partial)/(\partial z)(sin(z^3)cos(xy)) is cos(xy)cos(z^3)*3z^2

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(\partial)/(\partial z)(sin(z^3)cos(xy))

\frac{\partial}{\partial z} (sin (z^{3}) cos (x y))

cos (x y) cos (z^{3}) \cdot 3 z^{2}

Solution steps

\frac{\partial}{\partial z} (sin (z^{3}) cos (x y))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x y) \frac{\partial}{\partial z} (sin (z^{3}))

Apply the chain rule:

cos (z^{3}) \frac{\partial}{\partial z} (z^{3})

= cos (z^{3}) \frac{\partial}{\partial z} (z^{3})

\frac{\partial}{\partial z} (z^{3}) = 3 z^{2}

= cos (x y) cos (z^{3}) \cdot 3 z^{2}

f (x) = \frac{- 2 x}{x ^{5} - x - 1}

\int yz e^{x y} d x

y = x, (4, 2)

\int \frac{4 x ^{2} + 5 x + 4}{( x ^{2} + 1 ) ^{2}} d x

\int 2 sin (x) + sin (2 x) d x

What is (\partial)/(\partial z)(sin(z^3)cos(xy)) ?
The answer to (\partial)/(\partial z)(sin(z^3)cos(xy)) is cos(xy)cos(z^3)*3z^2