What is the limit as x approaches 0 of cos(4x) ?

The limit as x approaches 0 of cos(4x) is 1

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limit as x approaches 0 of cos(4x)

x \to 0 lim (cos (4 x))

1

Solution steps

x \to 0 lim (cos (4 x))

Plug in the value

x = 0

= cos (4 \cdot 0)

Simplify

cos (4 \cdot 0) : 1

= 1

(x^{2} + 1) y^{^{'}} + 4 x (y - 1) = 0

49 - x^{2}

f (x) = x^{3} - 3 x^{2} + 4 x + 5, x = 3

(1 + x)^{- \frac{7}{3}}, 4

y^{^{''}} - 64 y = 0

What is the limit as x approaches 0 of cos(4x) ?
The limit as x approaches 0 of cos(4x) is 1