What is the integral from-pi/9 to pi/9 of 2sin(3x)-tan(3x) ?

The integral from-pi/9 to pi/9 of 2sin(3x)-tan(3x) is 0

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integral from-pi/9 to pi/9 of 2sin(3x)-tan(3x)

\int_{- \frac{π}{9}}^{\frac{π}{9}} 2 sin (3 x) - tan (3 x) d x

0

Solution steps

\int_{- \frac{π}{9}}^{\frac{π}{9}} 2 sin (3 x) - tan (3 x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

2 sin (3 x) - tan (3 x) :

Odd

= 0

\frac{d}{d x} ((2 x^{3} + 4 x^{2}) (4 x^{2} + 2 x))

\int 225 - t^{2} d t

\frac{h w}{60}

\frac{d}{d x} (\frac{x ^{3} - 2}{x + 1})

\int x^{2} - 3 x + 2 d x

What is the integral from-pi/9 to pi/9 of 2sin(3x)-tan(3x) ?
The integral from-pi/9 to pi/9 of 2sin(3x)-tan(3x) is 0