What is the derivative of x^2-16ln(x^2) ?

The derivative of x^2-16ln(x^2) is 2x-(32)/x

What is the first derivative of x^2-16ln(x^2) ?

The first derivative of x^2-16ln(x^2) is 2x-(32)/x

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\frac{d}{d x} (x^{2} - 16 ln (x^{2}))

2 x - \frac{32}{x}

Solution steps

\frac{d}{d x} (x^{2} - 16 ln (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (16 ln (x^{2}))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (16 ln (x^{2})) = \frac{32}{x}

= 2 x - \frac{32}{x}

f (x) = 10 x - 12 + \frac{27}{x ^{4}}

t e^{- 4 t}

\frac{x ^{3}}{24} + \frac{2}{x}

\frac{\partial}{\partial x} (\frac{e ^{- x}}{x ^{2} + y ^{2}})

y^{^{''}} + 1.5 y^{^{'}} + 0.37 y = 0, y (0) = 2, y^{^{'}} (0) = 1

What is the derivative of x^2-16ln(x^2) ?
The derivative of x^2-16ln(x^2) is 2x-(32)/x
What is the first derivative of x^2-16ln(x^2) ?
The first derivative of x^2-16ln(x^2) is 2x-(32)/x