What is the solution for y^'= 1/(2yt)-y/(2t) ?

The solution for y^'= 1/(2yt)-y/(2t) is y=sqrt((-c_{1)+t)/t},y=-sqrt((-c_{1)+t)/t}

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y^'= 1/(2yt)-y/(2t)

y^{^{'}} = \frac{1}{2 y t} - \frac{y}{2 t}

y = \frac{- c _{1} + t}{t}, y = - \frac{- c _{1} + t}{t}

Solution steps

y^{'} (t) = \frac{1}{2 y t} - \frac{y}{2 t}

Solve separable ODE:

y = \frac{- c _{1} + t}{t}, y = - \frac{- c _{1} + t}{t}

y = \frac{- c _{1} + t}{t}, y = - \frac{- c _{1} + t}{t}

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What is the solution for y^'= 1/(2yt)-y/(2t) ?
The solution for y^'= 1/(2yt)-y/(2t) is y=sqrt((-c_{1)+t)/t},y=-sqrt((-c_{1)+t)/t}