What is area y=11x^2,y=x^2+7 ?

The answer to area y=11x^2,y=x^2+7 is -(7sqrt(14))/(3sqrt(5))+14sqrt(7/10)

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area y=11x^2,y=x^2+7

area

y = 11 x^{2}, y = x^{2} + 7

- \frac{7 14}{3 5} + 14 \frac{7}{10}

Decimal

7.80882 \dots

Solution steps

Apply the area formula:

\int_{- \frac{7}{10}}^{\frac{7}{10}} 11 x^{2} - (x^{2} + 7) d x

Solve

\int_{- \frac{7}{10}}^{\frac{7}{10}} 11 x^{2} - (x^{2} + 7) d x : - \frac{7 14}{3 5} + 14 \frac{7}{10}

The area is:

= - \frac{7 14}{3 5} + 14 \frac{7}{10}

n = 1 \sum \infty (1 + \frac{2}{n})^{2} e^{- 5 n}

5 x^{2} - 1 + 7 e^{x}

\frac{\partial}{\partial x} (\frac{3 y}{x})

y^{^{''}} + 6 y^{^{'}} + 25 = 0

y^{^{''}} + 6 y^{^{'}} + 10 y = 5 t - 2

What is area y=11x^2,y=x^2+7 ?
The answer to area y=11x^2,y=x^2+7 is -(7sqrt(14))/(3sqrt(5))+14sqrt(7/10)