What is the derivative of x^2*2^x ?

The derivative of x^2*2^x is 2^{1+x}x+ln(2)*2^xx^2

What is the first derivative of x^2*2^x ?

The first derivative of x^2*2^x is 2^{1+x}x+ln(2)*2^xx^2

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\frac{d}{d x} (x^{2} \cdot 2^{x})

2^{1 + x} x + ln (2) \cdot 2^{x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} \cdot 2^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 2^{x}

= \frac{d}{d x} (x^{2}) 2^{x} + \frac{d}{d x} (2^{x}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

= 2 x \cdot 2^{x} + 2^{x} ln (2) x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{x} = 2^{1 + x}

= 2^{1 + x} x + ln (2) \cdot 2^{x} x^{2}

2 x e^{x}

\frac{d}{d x} (e^{x^{2}} - 1)

\frac{d}{d x} (x \cdot e^{x} - 1)

\frac{\partial}{\partial x} (4 e^{x^{7} y})

\int x^{2} - 4 x + 29 d x

What is the derivative of x^2*2^x ?
The derivative of x^2*2^x is 2^{1+x}x+ln(2)*2^xx^2
What is the first derivative of x^2*2^x ?
The first derivative of x^2*2^x is 2^{1+x}x+ln(2)*2^xx^2