What is laplacetransform 4sin^2(t) ?

The answer to laplacetransform 4sin^2(t) is 8/(s(s^2+4))

Popular >

laplacetransform 4sin^2(t)

laplace transform

4 sin^{2} (t)

\frac{8}{s ( s ^{2} + 4 )}

Solution steps

L {4 sin^{2} (t)}

Rewrite using trig identities

L {2 - 2 cos (2 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {2} - 2 L {cos (2 t)}

L {2} : \frac{2}{s}

L {cos (2 t)} : \frac{s}{s ^{2} + 4}

= \frac{2}{s} - 2 \cdot \frac{s}{s ^{2} + 4}

Simplify

\frac{2}{s} - 2 \frac{s}{s ^{2} + 4} : \frac{8}{s ( s ^{2} + 4 )}

= \frac{8}{s ( s ^{2} + 4 )}

\frac{\partial}{\partial y} (cos (z))

e^{x} y^{^{'}} - e^{x} y = 1 - 2 x

\int \frac{e ^{4 t}}{t} d t

\frac{s - 1}{s ^{2} ( s ^{2} + 1 )}

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 4}{x})

What is laplacetransform 4sin^2(t) ?
The answer to laplacetransform 4sin^2(t) is 8/(s(s^2+4))