What is the limit as x approaches 0+of 1/(x^2-x) ?

The limit as x approaches 0+of 1/(x^2-x) is -infinity

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limit as x approaches 0+of 1/(x^2-x)

x \to 0 + lim (\frac{1}{x ^{2} - x})

- \infty

Solution steps

x \to 0 + lim (\frac{1}{x ^{2} - x})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{2} - x < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

\int x^{3} 7 - x^{2} d x

\frac{d}{d x} (5 + sin (x))

\int \frac{ln ( x )}{x ^{4}} d x

\frac{\partial}{\partial x} (\frac{x ^{2} - y ^{2}}{1 + x ^{2}})

y = 2 - x^{2}, y = 6 - 5 x

What is the limit as x approaches 0+of 1/(x^2-x) ?
The limit as x approaches 0+of 1/(x^2-x) is -infinity